SOLUTION: A box of chocolates contains 10 milk chocolates, 8 dark chocolates, and 6 white chocolates. Hannisa randomly chooses a chocolate, eats it, and then randomly chooses another chocola
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-> SOLUTION: A box of chocolates contains 10 milk chocolates, 8 dark chocolates, and 6 white chocolates. Hannisa randomly chooses a chocolate, eats it, and then randomly chooses another chocola
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Question 1193360: A box of chocolates contains 10 milk chocolates, 8 dark chocolates, and 6 white chocolates. Hannisa randomly chooses a chocolate, eats it, and then randomly chooses another chocolate. What is the probability that Hannisa choose a milk chocolate, and then, a white chocolate? Show your solution. Answer by math_tutor2020(3817) (Show Source):
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A = probability the first selection is a milk chocolate
A = (number of milk chocolates)/(number total)
A = (10)/(10+8+6)
A = 10/24
A = 5/12
B = probability the second selection is a white chocolate, given event A has happened
B = (number of white chocolates)/(number of chocolates left)
B = (6)/(24-1)
B = 6/23
A*B = probability of both events A and B occurring
A*B = (5/12)*(6/23)
A*B = (5*6)/(12*23)
A*B = (5*6)/(6*2*23)
A*B = (5)/(2*23)
A*B = 5/46
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