SOLUTION: I need to graph this equation: x+6=-5 it's supposed to be standard form like Ax+By=C My teacher said to use the numbers -2 -1 0 1 2 3 but they don't work.

Algebra ->  Coordinate Systems and Linear Equations -> SOLUTION: I need to graph this equation: x+6=-5 it's supposed to be standard form like Ax+By=C My teacher said to use the numbers -2 -1 0 1 2 3 but they don't work.      Log On


   

Question 119333: I need to graph this equation:
x+6=-5
it's supposed to be standard form like
Ax+By=C
My teacher said to use the numbers -2 -1 0 1 2 3
but they don't work.
Found 2 solutions by Fombitz, solver91311:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
x%2B6=-5
If you subtract 6 from both sides, you get
x%2B6-6=-5-6
x=-11
That is the standard form with A=1, B=0, and C=-11.
%281%29x%2B%280%29y=-11
So for any y value, x=-11.

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!
Let's go ahead and solve this for x first:
x%2B6=-5

Add -6 to both sides:

x=-11

Now let's put that in standard form:

Ax%2BBy=C

The A and C coefficients are easy, A=1 and C=-11. But there is no y term, so now what do we do? Another way to say there is no y term is to say there are zero ys in the equation, which means we can say that B=0.

Hence, standard form would be:

1x%2B0y=-11

Since none of the numbers in the set {-2,-1,0,1,2,3} make the equation true if you substitute them for x, substitute them for y instead. Since the coefficient on the y term is 0, you get the result x=-11 no matter what value you choose for y.

Your table of values would then be:


Giving you a set of points to plot. You should end up with a vertical line that crosses the x-axis at, yep, you guessed it, (-11,0)

Hope that helps,
John