SOLUTION: Analyze the problem and Sketch the figure of the given situation. A. For y=ln2x , determine the equation of a tangent line parallel to 2x-3y+1=0.

Algebra ->  Test -> SOLUTION: Analyze the problem and Sketch the figure of the given situation. A. For y=ln2x , determine the equation of a tangent line parallel to 2x-3y+1=0.      Log On


   



Question 1193313: Analyze the problem and Sketch the figure of the given situation.
A. For y=ln2x , determine the equation of a tangent line parallel to 2x-3y+1=0.

Answer by Alan3354(69443) About Me  (Show Source):
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For y=ln2x , determine the equation of a tangent line parallel to 2x-3y+1=0.
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If you mean y = ln(2x):
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Find the slope of the given line, m
m = 2/3
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Find the slope of y = ln(2x)
Find the 1st derivative
y' = (1/2x)*2 = 1/x is the slope at any point (x,ln(2x))
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1/x = 2/3
x = 3/2, y = ln(3)
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y-ln(3) = (2/3)*(x - 1.5)