Notice that can be written as the sum of squares:
Draw a right triangle
Always put the simpler expression on the adjacent side. Since 1
is simpler than ex, we put it on the adjacent side.
The sign between the squares is + so we put the more complicated
expression on the opposite side. [If it had been - we would have
put the more complicated expression on the hypotenuse.]
So
Solve for x by taking natural logs of both sides:
We find dx by multiplying the derivative by dθ
Then we use the Pythagorean theorem to label the
missing side, which is the hypotenuse.
Now we're ready to substitute:
We substitute for dx
Now here's a trick. Observe that the denominator
equals the square of the hypotenuse, and since
the denominator is just sec2(θ)
Now the sec2(θ)'s cancel:
Now we look back at the triangle and find that
<-- final answer
Edwin