SOLUTION: Find the probabilities ,using the standard normal distribution. A. P(-23 < z < 0.79)

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Question 1193058: Find the probabilities ,using the standard normal distribution.
A. P(-23 < z < 0.79)

Answer by ikleyn(52794) About Me  (Show Source):
You can put this solution on YOUR website!
.

The normal distribution curve is a bell shaped curve.

This question is to determine the area under the normal distribution curve
between the given scores.

It can be done in different ways:

        - manually,   or

        - using online calculators,    or

        - using your pocket calculator.


                    MANUALLY


To do the job manually,  use this  Table representing  AREA  to the  LEFT  of the  Z-score
https://www.math.arizona.edu/~rsims/ma464/standardnormaltable.pdf

On how to do it,  see this Internet text source
http://statisticshelper.com/how-to-use-the-z-table


                USING  ONLINE  CALCULATOR


To do the job using an online  (free of charge)  calculator,  go to this web-site
https://onlinestatbook.com/2/calculators/normal_dist.html


Input the given parameters of each question into an appropriate window of the calculator and get the answers
to your questions.


The calculator has perfect description and design,  as well as clear visual interface, which prevents you of making errors.
So  EVERY  person,  even beginner,  may work with it on his or her own,  even having minimum knowledge on the subject.


                USING  YOUR  POCKET  CALCULATOR


On how to use it,  see a text description in  THIS  Internet source / site
https://mathbits.com/MathBits/TISection/Statistics2/normaldistribution.htm


Or see these  Youtube video-lessons

https://www.youtube.com/watch?v=bVdQ7OzGvU0     (for  Casio fx-991 MS)
https://www.youtube.com/watch?v=yYpMkgB20C4     (for  TI-83  or  TI-84 calculators)


I recommend you to play with the online calculator first.
If you are unfamiliar with the subject, playing with the online calculator will help you a lot !


After learning it, you will be able to solve this problem  (and thousand other similar and different problems)  ON  YOUR  OWN,
without asking for help from outside.