Question 1192996: joy invested a certain amount at 9%, twice that amount at 10%, and three times that amount at 11%. find the amount invested at each rate if the total yearly income from the three investments was Php27,900.00. What is the amount of the investment at 10%
Found 2 solutions by ikleyn, greenestamps:
Answer by ikleyn(52781)   (Show Source):
You can put this solution on YOUR website! .
Write equation for the total interest
0.09*x + 0.1*(2x) + 0.11*(3x) = 27900
where x is the amount invested at 9%.
Simplify this equation and find x
x =  = 45000.
ANSWER. Php 45000 invested at 9%; Php 90000 invested at 10% and Php 135000 invested at 11%.
Solved.
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Your second question is a part of the first question.
Why you placed your second question separately, is unclear to me . . . it is covered in full by the first question.
Answer by greenestamps(13200)  (Show Source):
You can put this solution on YOUR website!
The amounts invested at 9%, 10%, and 11% were x, 2x, and 3x, respectively.
So 1/6 of the total was invested at 9%; 2/6 = 1/3 at 10%, and 3/6 = 1/2 at 11%.
The average percent return on the investment was  , or 10 1/3%. As a fraction that percentage is 
27,900 return at a rate of 10 1/3% means the amount invested was 
ANSWERS:
1/6 of Php270,000 = Php45,000 at 9%
1/3 of Php270,000 = Php90,000 at 10%
1/2 of Php270,000 = Php135,000 at 11%
CHECK:
.09(45000)+.10(90000)+.11(135000)=4050+9000+14850=27900
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