SOLUTION: Simplify 8m^(1/3)n^(-3/2)(-2m^(-2/3)n^(1/3))^-4

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Simplify 8m^(1/3)n^(-3/2)(-2m^(-2/3)n^(1/3))^-4      Log On


   



Question 1192945: Simplify
8m^(1/3)n^(-3/2)(-2m^(-2/3)n^(1/3))^-4

Found 2 solutions by MathLover1, greenestamps:
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!
8m%5E%281%2F3%29%2An%5E%28-3%2F2%29%28-2m%5E%28-2%2F3%29%2An%5E%281%2F3%29%29%5E%28-4%29

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=%288m%5E%281%2F3%29%2Fn%5E%283%2F2%29%29%28m%5E%288%2F3%29%2F16n%5E%284%2F3%29%29

=%288m%5E%281%2F3%29%2Am%5E%288%2F3%29%29%2F%28n%5E%283%2F2%29%2A16n%5E%284%2F3%29%29

=%288m%5E%281%2F3%2B8%2F3%29%29%2F%2816n%5E%283%2F2%2B4%2F3%29%29

=%288m%5E%281%2F3%2B8%2F3%29%29%2F%2816n%5E%289%2F6%2B8%2F6%29%29

=%288m%5E3%29%2F%2816n%5E%2817%2F6%29%29......simplify

=m%5E3%2F%282n%5E%2817%2F6%29%29



Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


There is nothing wrong with the solution from the other tutor.

However, because of the way the software on this web site displays expressions with exponents, her work is hard to follow.

In addition, in practice the process of simplifying an expression like this is (for most students at least) is far easier if we look at the constants and each variable separately.

Here is what I would do with this....

8m%5E%281%2F3%29n%5E%28-3%2F2%29%28-2m%5E%28-2%2F3%29n%5E%281%2F3%29%29%5E-4 -->

(1) Constants....

The constant is %288%29%28%28-2%29%5E%28-4%29%29=%288%29%281%2F16%29=1%2F2

(2) variable m....

The exponents are 1%2F3 and %28%28-2%2F3%29%28-4%29%29=8%2F3
Add the exponents: 1%2F3%2B8%2F3=9%2F3=3

(3) variable n....

The exponents are -3%2F2 and %281%2F3%29%28-4%29=-4%2F3
Add the exponents: %28-3%2F2%29%2B%28-4%2F3%29=%28-9%2F6%29%2B%28-8%2F6%29=-17%2F6

Combine the three parts of the expression to get the final simplified expression:

ANSWER: %281%2F2%29%28m%5E3%29%28n%5E%28-17%2F6%29%29 or %28m%5E3%29%2F%28%282%29n%5E%2817%2F6%29%29

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Clarification of a point the student asked about....

In the factor "1/2", the 2 is in the denominator; so when all the parts are combined, the "2" is still in the denominator (and since the "1" of the fraction is in the numerator, we don't need to write it in the combined form of the answer).

I've added parentheses around the "2" in the denominator of the final form of the answer to try to help make this clear.