SOLUTION: at the beginning of the Alay Lakad, Rizza and Angel are 30km apart. if they leave at the same time and walk in the same direction, rizza overtakes angel in 60 hours. if they walk t
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Question 119291: at the beginning of the Alay Lakad, Rizza and Angel are 30km apart. if they leave at the same time and walk in the same direction, rizza overtakes angel in 60 hours. if they walk towards to each other, they meet in 5 hours. what are their speed? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! R and A are 30km apart. if they leave at the same time and walk in the same direction, R overtakes A in 60 hours. if they walk towards to each other, they meet in 5 hours. what are their speed?
:
r = R's speed
and
a = A's speed
:
Write a distance equation for each trip, Distance = time * speed:
:
Same direction:
60r - 30 = 60a
60r - 60a = 30
r - s = .5; simplified divided equation by 60
:
Toward each other (total both traveled = 30 km)
5r + 5a = 30
r + a = 6; simplified, divided equation by 5
:
Use these two equation for elimination of a:
r + a = 6
r - a = .5
--------------add
2r +0a = 6.5
r =
r = 3.25 km/h is R's speed
:
Use r - a = .5 to find a's speed
3.25 - a = .5
-a = .5 - 3.25
-a = -2.75
a = 2.75 km/h is A's speed
:
:
Check solutions in original equations
60r - 60a = 30
60(3.25) - 60(2.75) =
195 - 165 = 30
and
5r + 5a = 30
5(3.25) + 5(2.75) =
16.25 + 13.75 = 30; confirms our solutions
:
Did this make sense to you? Any questions?
