SOLUTION: A particular fruit's weights are normally distributed, with a mean of 657 grams and a standard deviation of 36 grams you pick 23 fruit at random, what is the probability that their
Algebra ->
Probability-and-statistics
-> SOLUTION: A particular fruit's weights are normally distributed, with a mean of 657 grams and a standard deviation of 36 grams you pick 23 fruit at random, what is the probability that their
Log On
Question 1192863: A particular fruit's weights are normally distributed, with a mean of 657 grams and a standard deviation of 36 grams you pick 23 fruit at random, what is the probability that their mean weight will be between 639 grams and 649 grams? (Round to 4 decimal places.) Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! z=(x-mean)/sd/sqrt(n)
z(639)=(639-657)36/sqrt(23)
=-2.398
z(649)=(649-657)/36/sqrt(23)
=-8*sqrt(23)/36)=-1.066
probability of z between those two values is 0.1350
