SOLUTION: Based on all student records at Camford University, students spend an average of 6.60 hours per week playing organized sports. The population’s standard deviation is 3.00 hours p
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Question 1192824: Based on all student records at Camford University, students spend an average of 6.60 hours per week playing organized sports. The population’s standard deviation is 3.00 hours per week. Based on a sample of 49 students, Healthy Lifestyles Incorporated (HLI) would like to apply the central limit theorem to make various estimates.
a. Compute the standard error of the sampling distribution of sample means. (Round your answer to 2 decimal places.)
b. What is the chance HLI will find a sample mean between 5.9 and 7.3 hours? (Round your z-and standard error values to 2 decimal places. Round your intermediate values and final answer to 4 decimal places.)
c. Calculate the probability that the sample mean will be between 6.2 and 7 hours. Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! SE=sd/sqrt()=3/7=0.43 hours
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z=(5.9-6.6)/0.43=-1.63 and therefore between that and +1.63
probability is 0.8969
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it is now .4/0.43 and -.4/4.3 which is z=-0.93 to +0.93, or probability 0.6476
