SOLUTION: A ball is thrown from 1 m above ground level. It's velocity is v(t) = 29.4-9.8t ms^-1.
a. Find the displacement function s(t) (I found this: 29.4-4.9t^2+1
b. Find the maximu
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-> SOLUTION: A ball is thrown from 1 m above ground level. It's velocity is v(t) = 29.4-9.8t ms^-1.
a. Find the displacement function s(t) (I found this: 29.4-4.9t^2+1
b. Find the maximu
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Question 1192812: A ball is thrown from 1 m above ground level. It's velocity is v(t) = 29.4-9.8t ms^-1.
a. Find the displacement function s(t) (I found this: 29.4-4.9t^2+1
b. Find the maximum height reached by the ball (need help in this). Found 3 solutions by Boreal, ikleyn, Alan3354:Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! s(t)=-4.9t^2+29.4t+1 (you need a "t" for the second term, since you are anti-differentiating 29.4 dt)
the vertex for this negative quadratic is at -b/2a=-29.4/-9.8=3
so it is at t=3 seconds.
s(3)=88.2-44.1+1=45.1 m
You can put this solution on YOUR website! .
A ball is thrown from 1 m above ground level. It's velocity is v(t) = 29.4-9.8t ms^-1.
a. Find the displacement function s(t) (I found this: 29.4-4.9t^2+1
b. Find the maximum height reached by the ball (need help in this).
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