SOLUTION: Show that whenever n ≥ 3, fn > ßn-2 , where ß = (1 + √ 5)∕2.

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Question 1192800: Show that whenever n ≥ 3, fn > ßn-2 , where ß = (1 + √ 5)∕2.
Answer by ikleyn(52756) About Me  (Show Source):
You can put this solution on YOUR website!
.
Show that whenever n ≥ 3, fn > ßn-2 , where ß = (1 + √ 5)∕2.
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Makes no sense.


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                    To the managers of this project  ( ! )


As  I  notice,  nonsensical messages arrive to this forum,  created by persons illiterated in  Math.


Examples are these posts

https://www.algebra.com/algebra/homework/logarithm/logarithm.faq.question.1192804.html

https://www.algebra.com/algebra/homework/Linear-equations/Linear-equations.faq.question.1192802.html

https://www.algebra.com/algebra/homework/Pythagorean-theorem/Pythagorean-theorem.faq.question.1192801.html

https://www.algebra.com/algebra/homework/logarithm/logarithm.faq.question.1192800.html



I ask you please to take all necessary measures and remove the person/(persons) who created these posts
from their positions in the project due to their inability to do their job properly.