SOLUTION: A Math teacher has 3 Algebra books, 5 Geometry books, 4 Trigonometry books, and 3 Statistics books. If Statistics, Trigonometry, Algebra, then Geometry books are arranged in that o

Algebra ->  Permutations -> SOLUTION: A Math teacher has 3 Algebra books, 5 Geometry books, 4 Trigonometry books, and 3 Statistics books. If Statistics, Trigonometry, Algebra, then Geometry books are arranged in that o      Log On


   



Question 1192735: A Math teacher has 3 Algebra books, 5 Geometry books, 4 Trigonometry books, and 3 Statistics books. If Statistics, Trigonometry, Algebra, then Geometry books are arranged in that order, in how many ways can this be done?. Show the solution.
Answer by math_helper(2461) About Me  (Show Source):
You can put this solution on YOUR website!

The problem statement implies each subject category will remain together as a group. If we further assume that "in that order" means the same as "left to right" then there are:
3! * 4! * 3! * 5! = 6 * 24 * 6 * 120 = 103680 ways to arrange the books.

Details/insights:
For N unique objects, there are N! arrangements that are unique.
examples:
Two objects AB can be arranged as AB or BA (2! = 2)
Three objects ABC can be arranged as ABC, ACB, BAC, BCA, CAB, or CBA (3! = 6)
etc.