SOLUTION: A particle is moving in the positive direction, away from the origin along the graph of y = x^2. At what point on the curve are the x and y-coordinates of the particle changing at

Algebra ->  Rational-functions -> SOLUTION: A particle is moving in the positive direction, away from the origin along the graph of y = x^2. At what point on the curve are the x and y-coordinates of the particle changing at       Log On


   



Question 1192715: A particle is moving in the positive direction, away from the origin along the graph of y = x^2. At what point on the curve are the x and y-coordinates of the particle changing at the same rate?
Answer by ikleyn(52788) About Me  (Show Source):
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A particle is moving in the positive direction, away from the origin along the graph of y = x^2.
At what point on the curve are the x and y-coordinates of the particle changing at the same rate?
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From  y = x^2,  we have  dy = 2x*dx.    (1)


They want dy = dx, so we put  dy = dx = c  and  substitute this (unknown) value of "c" into equation (1)

    c = 2x*c.


Canceling "c" in both sides, we get  x = 1%2F2 = 0.5.


So, the  ANSWER  is the point  (x,y) = (0.5,0.25).

Solved.