SOLUTION: Find sin(2x), cos(2x), and tan(2x) from the given information. csc(x) = 8, tan(x) < 0

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Question 1192632: Find sin(2x), cos(2x), and tan(2x) from the given information.
csc(x) = 8, tan(x) < 0

Found 2 solutions by mananth, ikleyn:
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
csc(x)=8 Given)
⇒sinx=1/8
cos^2x=1−sin^2x
⇒cos^2x=1−1/64=63/64
⇒cosx=3√7/8
1. sin2x=2sinxcosx
sin2x=2×18×3√78
sin2x=3√732
2. cos2x=2cos^2x−1
cos2x=(2×63/64)−1
cos2x=(63/32)
3. tan2x=sin2xcos2x
tan2x=3√7/31


Answer by ikleyn(52803) About Me  (Show Source):
You can put this solution on YOUR website!
.
Find sin(2x), cos(2x), and tan(2x) from the given information.
csc(x) = 8, tan(x) < 0
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        The solution by @mananth is elementary wrong.
        I came to bring a correct soluition.


You are given that csc(x) = 8, tan(x) < 0.

It means that  sin(x) = 1%2F8,  tan(x) < 0;  hence x is the angle in QII, second quadrant.


It implies that cos(x) = -sqrt%281-sin%5E2%28x%29%29 = -sqrt%281-1%2F64%29 = -sqrt%2863%2F64%29 = -%283%2Asqrt%287%29%29%2F8.


Now  sin(2x) = 2*sin(x)*cos(x) = 2%2A%281%2F8%29%2A%28%28-3%2Asqrt%287%29%29%2F8%29 = -%283%2Asqrt%287%29%29%2F32;


     cos(2x) = cos^2(x) - sin^2(x) = 63%2F64 - 1%2F64 = 62%2F64 = 31%2F32.


     tan(2x) = %28sin%282x%29%29%2F%28cos%282x%29%29 = -%283%2Asqrt%287%29%29%2F31.

Solved.