SOLUTION: In a figure, curve A whose equation is y=(x+a)^2, passes through the point (4,0). Curve B whose equation is y=(x+a)^2+b, passes through the point (4,-9). a)Calculate the values

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: In a figure, curve A whose equation is y=(x+a)^2, passes through the point (4,0). Curve B whose equation is y=(x+a)^2+b, passes through the point (4,-9). a)Calculate the values      Log On


   

Question 1192552: In a figure, curve A whose equation is y=(x+a)^2, passes through the point (4,0).
Curve B whose equation is y=(x+a)^2+b, passes through the point (4,-9).
a)Calculate the values of a and b
b)if the curve B intersects the x-axis at point (p,0) and (q,0), calculate the values of p and q
c)if curve B intersects the y-axis at the point (0,r), calculate the value of r.
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
y=(x+a)^2
0=(4+a)^2; a=-4
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y=(x-4)^2+b the vertex is (-a, b) or (4, -9)
b=-9
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0=(x-4)^2-9=x^2-8x+7=(x-1)(x-7)
p and q are 1 and 7 or 7 and 1
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r=(0-4)^2-9=7
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