Question 1192548: The foci are at (3, 5) and (1, 5), and the ellipse has eccentricity 0.25.
Answer by greenestamps(13209)   (Show Source):
You can put this solution on YOUR website!
The foci are (1,5) and (3,5); so the center is (2,5), and the distance from the center to each focus, c, is 1.
The eccentricity 0.25=1/4 is c/a, where a is the semi-major axis; so a=4.
c^2=a^2-b^2 where b is the semi-minor axis, so b is sqrt(15).
The major axis is horizontal, so the equation is
|
|
|
