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Question 1192491: Find the equation of the tangent to;
f(x) = e^-x at the point where x=2.
So I know dy/dx=-1/e^x, but don't understand how I can sub that x value in the original equation and find the y value.
Answer by ikleyn(52786) (Show Source):
You can put this solution on YOUR website! .
Find the equation of the tangent to;
f(x) = e^-x at the point where x=2.
So I know dy/dx=-1/e^x, but don't understand how I can sub that x value in the original equation
and find the y value.
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You correctly determined the derivative function = - .
To proceed further, you should substitute x= 2 into the formula.
Doing this way, you will find the value of the derivative at the point x= 2, which is the slope of the function
f(x) =
at the point x= 2.
So, the slope is m = - .
Now you know the point on the plot of the function: it is ( , ) = ( , );
and you know the slope: it is m = - .
So, the equation of the tangent line is = , or
y - = - .
It is your ANSWER.
You can also use any other EQUIVALENT form of the last equation.
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Solved and explained.
If you have question/questions, then let me know.
If you will post your questions, please refer to the problem's ID number 1192491 .
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