SOLUTION: Can you help me with these 2 problems? -3x+6 < 12 (the -3x and 6 have are both divided by 2, I couldn't show it because I didn't know how) and 11y+13 > -1

Algebra ->  Inequalities -> SOLUTION: Can you help me with these 2 problems? -3x+6 < 12 (the -3x and 6 have are both divided by 2, I couldn't show it because I didn't know how) and 11y+13 > -1      Log On


   

Question 119228: Can you help me with these 2 problems?
-3x+6 < 12 (the -3x and 6 have are both divided by 2, I couldn't show it because I didn't know how)
and
11y+13 > -1
Found 2 solutions by edjones, josmiceli:
Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
(-3x+6)/2 < 12
2(-3x+6)/2 < 2*12
-3x+6<24 No fractions
-3x+6-6<24-6
-3x<18
-3x/-3>18/-3 Reverse the sign when dividing or mult. by a neg. numb.
x>-6
.
11y+13>-1
11y+13-13>-1-13
11y>-14
11y/11>-14/11
y>-14/11
.
Ed

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
%28-3x+%2B+6%29%2F2+%3C+12
multiply both sides by 2
-3x+%2B+6+%3C+24
subtract 6 from both sides
-3x+%3C+18
divide both sides by -3 and change the < to >
x+%3E+-6 answer
-------------------
11y+%2B+13+%3E+-1
11y+%3E+-14
y+%3E+-%2814%2F11%29 answer
------------------
You can plug these answers back into the original inequalities
and check them. Say, for the 2nd one, try -%2813%2F11%29 which
is slightly greater (more positive) than -%2814%2F11%29