SOLUTION: The salary of 500 employees of a production home follows normal distribution with mean 5700 taka as well as SD 500.Find probability of
(a)salary more than 5800 taka
(b)salary bet
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-> SOLUTION: The salary of 500 employees of a production home follows normal distribution with mean 5700 taka as well as SD 500.Find probability of
(a)salary more than 5800 taka
(b)salary bet
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Question 1192247: The salary of 500 employees of a production home follows normal distribution with mean 5700 taka as well as SD 500.Find probability of
(a)salary more than 5800 taka
(b)salary between 5200-6000 taka Answer by Theo(13342) (Show Source):
You can put this solution on YOUR website! mean = 5700
standard deviation = 500
z-score = (x - m) / s
x is the raw score
m is the mean
s is the standard deviation.
when x = 5800, z = (5800 - 5700) / 500 = .2
i used the z-score table at https://www.rit.edu/academicsuccesscenter/sites/rit.edu.academicsuccesscenter/files/documents/math-handouts/Standard%20Normal%20Distribution%20Table.pdf
that table gives you the area to the left of the z-score.
area to the left of a z-score of .2 = .57926
area to the right of that z-score = 1 - .57926 = .42074
that's the probability of getting a score greater than 5800.
to get the probability between two z-scores, you want to get the low z-score and the high z-score and take the area to the left of each and then subtract the smaller area from the larger area.
when x = 5200, z = (5200 - 5700) / 500 = -1.
area to the left of that z-score = .15866
when x = 6000, z = (6000 - 5700) / 500 = .6
area to the left of that z-score = .72575
area in between = .72575 - .15866 = .56709
that's the probability of getting a score between 5200 and 6000.
