Question 1192086: Given the digits 1,2,4,6,8 and 9, how many four - digit numbers can be formed if repetition is not allowed.
Answer by ikleyn(52782) (Show Source):
You can put this solution on YOUR website! .
Any of 6 given digits in the left-most position, giving 6 options;
any of remaining 5 digits in the next position, giving 5 options;
any of remaining 4 digits in the next position, giving 4 options;
any of remaining 3 digits in the last position, giving 3 options.
The ANSWER is the product of the number of options in each position
6*5*4*3 = 360 different numbers.
Solved.
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See the lesson
- Special type permutations problems
in this site. Find there many solved similar problems and learn the subject from there.
Also, you have this free of charge online textbook in ALGEBRA-II in this site
- ALGEBRA-II - YOUR ONLINE TEXTBOOK.
The referred lesson is the part of this online textbook under the topic "Combinatorics: Combinations and permutations".
Save the link to this textbook together with its description
Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson
into your archive and use when it is needed.
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