SOLUTION: Three judges A, B and C must make a decision by majority's vote. They make their individual decision independently. It is known that the judges make a correct decision with probabi

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Question 1192064: Three judges A, B and C must make a decision by majority's vote. They make their individual decision independently. It is known that the judges make a correct decision with probabilities A - 0.79, B - 0.65 and C 0.79. What is the chance that their decision will be correct? If their collective decision was correct, what is the chance of judge's A decision being the right one? Or what is the probability that only B and C had the right decision?
Answer by math_tutor2020(3817) About Me  (Show Source):
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P(A) = probability that judge A makes the correct decision
P(B) and P(C) represent similar ideas for the other two judges.

Given probabilities
P(A) = 0.79
P(B) = 0.65
P(C) = 0.79

Their complements
P(~A) = 1 - P(A) = 1 - 0.79 = 0.21
P(~B) = 1 - P(B) = 1 - 0.65 = 0.35
P(~C) = 1 - P(C) = 1 - 0.79 = 0.21
which represent the probabilities of making the incorrect decision.

P(A and B only) = P(A, B, ~C)
P(A and B only) = P(A)*P(B)*P(~C)
P(A and B only) = 0.79*0.65*0.21
P(A and B only) = 0.107835
Let x%5B1%5D+=+0.107835

P(B and C only) = P(~A, B, C)
P(B and C only) = P(~A)*P(B)*P(C)
P(B and C only) = 0.21*0.65*0.79
P(B and C only) = 0.107835
Let x%5B2%5D+=+0.107835

P(A and C only) = P(A, ~B, C)
P(A and C only) = P(A)*P(~B)*P(C)
P(A and C only) = 0.79*0.35*0.79
P(A and C only) = 0.218435
Let x%5B3%5D+=+0.218435

P(A and B and C) = P(A)*P(B)*P(C)
P(A and B and C) = 0.79*0.65*0.79
P(A and B and C) = 0.405665
Let x%5B4%5D+=+0.405665

Cases x%5B1%5D through x%5B3%5D represent situations where exactly two judges get the right decision.
Case x%5B4%5D is when all three judges make the correct ruling.
All four represent when at least two judges get the correct ruling.

Add up the x%5B1%5D through x%5B4%5D



The probability that at least two judges reach the correct decision, and therefore get the correct overall ruling, is 0.83977

Cases x%5B1%5D, x%5B3%5D, and x%5B4%5D represent situations where judge A made the correct ruling that led to the overall ruling being correct.
The sum of these x values is x%5B1%5D%2Bx%5B3%5D%2Bx%5B4%5D+=+0.731935

Dividing that second sum over the first sum calculated earlier will get us
0.731935/0.83977 = 0.871590
which is approximate.
This is the probability of judge A being correct given the overall ruling was correct.
This takes care of the second question mentioned.

For the third question, we go back to case x%5B2%5D which is when judges B and C are correct, but judge A is not correct.

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Summary:

What is the chance that their decision will be correct?
0.83977

If their collective decision was correct, what is the chance of judge's A decision being the right one?
0.871590

What is the probability that only B and C had the right decision?
0.107835