Question 1191996: The probability of a higher jump clearing 1.8m on any jump is 0.6,what is the probability of his clearing 1.8 m in precisely three out of seven jumps??
Answer by greenestamps(13203)   (Show Source):
You can put this solution on YOUR website!
The probability of his clearing is 0.6, so on any one jump the probability that he clears is 0.6 and the probability that he fails is 0.4.
So on any given sequence of 7 jumps, the probability that he clears 3 times and fails 4 times is (0.6^3)*(0.7^4).
The number of different sequences of 7 jumps in which he clears 3 times is "7 choose 3", C(7,3).
ANSWER: C(7,3)*(0.6^3)*(0.7^4)
You can do the calculations....
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