SOLUTION: A line passes through A(-2, 1) and B(3, 4). Find the point P on AB extended through B so that P is twice as far from A as from B. (b) the point Q on AB extended through B so that P

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: A line passes through A(-2, 1) and B(3, 4). Find the point P on AB extended through B so that P is twice as far from A as from B. (b) the point Q on AB extended through B so that P      Log On


   



Question 1191934: A line passes through A(-2, 1) and B(3, 4). Find the point P on AB extended through B so that P is twice as far from A as from B. (b) the point Q on AB extended through B so that P is twice as far from B as from A.
Answer by ikleyn(52787) About Me  (Show Source):
You can put this solution on YOUR website!
.
A line passes through A(-2, 1) and B(3, 4).
(a) Find the point P on AB extended through B so that P is twice as far from A as from B.
(b) the point Q on AB extended through B so that P is twice as far from B as from A.
~~~~~~~~~~~~~~~~~

(a)  From A to B, there are 5 units along x-axis and 3 units along y-axis.


     Hence, to get point P, you should move 5 units along x-axis from B
                                        and 3 units along y-axis from B.


     Thus the destination point P is  P = (3+5,4+3) = (8,7).    ANSWER




(b)  Such point Q does not exist.


     (simply because AQ is always longer than BQ).

Solved.