Question 1191833: Let U = {q, r, s, t, u, v, w, x, y, z}
A = {q, s, u, w, y}
B = {q, s, y, z}
C = {v, w, x, y, z}.
Determine the following.
A ∩ B'
Found 2 solutions by Edwin McCravy, greenestamps:
Answer by Edwin McCravy(20064)   (Show Source):
You can put this solution on YOUR website!
A ∩ B'
Substitute {q, s, u, w, y} for A and {q, s, y, z} for B:
{q, s, u, w, y} ∩ {q, s, y, z}'
Take care of the " ' " first. That means "complement", which means
to take all the elements of U that are not members of {q, s, y, z}.
So in place of {q, s, y, z}' we write {r, t, u, v, w, x}.
{q, s, u, w, y} ∩ {r, t, u, v, w, x}
Now " ∩ " (intersection) says to take ONLY the elements which are
IN COMMON to both sets. That is, only those elements which are
contained in both sets on the left and right of ∩. There are only
two:
{u, w} <--answer
Edwin
Answer by greenestamps(13209)  (Show Source):
You can put this solution on YOUR website!
The answer from the other tutor is fine; however, with relatively small sets like this, there is an easier way to get to the answer.
The set A ∩ B' consists of all the elements of A that are NOT in B. So start with the set A and eliminate any elements that are also in B.
q? no - also in B
s? no - also in B
u? yes -- not in B
w? yes -- not in B
y? no - also in B
ANSWER: A ∩ B' = {u,w}
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