Question 1191820: 2. The guidance counselor of Sinalhan Integrated High School conducted a survey to Grade 10 students on
what Senior High School Strand they will enroll next year. The breakdown of the survey that involves only
ABM and HUMSS strands is shown in the table below.
Strand Male (M) Female (F) Total
ABM (A) 92 79 171
HUMSS (H) 102 44 146
Total 194 123 317
Consider the following problems involving the situation above.
a. Find the probability that the student chose HUMSS, given that he was a male.
b. Find the probability that the student was a male, given that he chose HUMSS.
c. Find the probability that the student was a female, given that she chose ABM.
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! -------------M--F-Total
ABM (A). 92 79 171
HUMSS (H) 102 44 146
Total 194 123 317
Given male (194) probability code HUMSSS its 92/194=0.474
Given choose HUMSS (146), prob. was a male is 102/146=0.699
Given chose ABM (171), prob. was female is 79/171=0.462
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