Question 1191713: The probability of rain on first 3 days of august is as follows:
Day probability gain
first day 3/10
2nd day if rain on day 1 is 5/10
if no rain of day 1 is 2/10
3rd day if rain on day 1 and day 2 are 9/10
if rain on day 1 only is 5/10
if rain on day 2 only is 3/10
if no rain on day 1 and day 2 are 5/10
what is the probability of rain on atleast 2 out of 3 days?
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! ================rain 0.3===========No rain 0.7
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=============R 0.5------NR 0.5---------R(0.2)---------NR(0.8).Here there is an inconsistency because the product is 0.5 with one multiplier 0.7, but it is a dichotomous outcome and one has already been specified as 0.2, so NR has to be 0.8
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=========R (0.9)--NR(0.1)--R(0.5)--NR (0.5)----R(0.3)--NR(0.7)---R0.5---NR0.5
products. 0.135-----0.015----0.075--------------0.042
Those are the instances with 2 or more days of rain and the probabilities add to 0.267.
Check the wording on inconsistency above.
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