SOLUTION: Mr. Milling mixed orange juice, cranberry juice and gingerale in the ratio of 4:3:5 to make punch. If he made 6 liters of punch , how many liters of gingerale did he use?

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: Mr. Milling mixed orange juice, cranberry juice and gingerale in the ratio of 4:3:5 to make punch. If he made 6 liters of punch , how many liters of gingerale did he use?       Log On


   

Question 1191183: Mr. Milling mixed orange juice, cranberry juice and gingerale in the ratio of 4:3:5 to make punch. If he made 6 liters of punch , how many liters of gingerale did he use?
Found 2 solutions by ikleyn, greenestamps:
Answer by ikleyn(52787) About Me  (Show Source):
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.

6 liters of the punch are composed of 4+3+5 = 12 equal parts/volumes.


So, each of these parts is  6/12 = 0.5 liters.


Hence, the volume of ginger ale is 5 times 0.5 liters, or 2.5 liters.    ANSWER

Solved.



Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


The fraction of ginger ale in the punch is 5/(4+3+5) = 5/12.

The amount of ginger ale in 6 liters of punch is %285%2F12%29%2A6=5%2F2=2.5

ANSWER: 2.5 liters of ginger ale