SOLUTION: The smallest of three consecutive integers is 32 less than the sum of the two larger integers. Find the three integers.

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Question 1191174: The smallest of three consecutive integers is 32 less than the sum of the two larger integers. Find the three integers.
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
The smallest of three consecutive integers is 32 less than the sum of the two larger integers. Find the three integers.
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n = (n+1) + (n+2) - 32
Solve for n