SOLUTION: Solve triangle ABC. (If an answer does not exist, enter DNE. Round your answers to one decimal place.)
b = 69, c = 35, ∠A = 72°
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-> SOLUTION: Solve triangle ABC. (If an answer does not exist, enter DNE. Round your answers to one decimal place.)
b = 69, c = 35, ∠A = 72°
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Question 1191140: Solve triangle ABC. (If an answer does not exist, enter DNE. Round your answers to one decimal place.)
b = 69, c = 35, ∠A = 72° Found 2 solutions by josgarithmetic, Theo:Answer by josgarithmetic(39620) (Show Source):
You can put this solution on YOUR website! Drawing and labeling your description, you will find that angle at point A is between the two sides of length b( 69 units) and c (35 units). You can use Law Of Cosines, and then any other skills and properties that you can identify.
the sum of the angles is 180 degrees, as it should be.
the ratio of a / sine(A) = b / sine(B) = c/sine(C) is the same for all 3, as it should be.
that ratio was 70.482862 for all three.
the first thing i did was find the value of a using the law of cosines formula of:
a^2 = b^2 + c^2 - 2*a*b*cos(A).
the formula became:
a^2 = 69^2 + 35^2 - 2*69*35*cos(72) = 4493.447917
a = sqrt(4493.447917) = 67.03318519
once i got that, i was able to get the other values using the law of sines formula of:
a/sin(A) = b/sin(B) = c/sin(C)
(