SOLUTION: 3x-3y+3z=-27 2x+2y+3z=-3 -3x+2y+2z=-3

Algebra ->  Coordinate Systems and Linear Equations -> SOLUTION: 3x-3y+3z=-27 2x+2y+3z=-3 -3x+2y+2z=-3      Log On


   



Question 119112: 3x-3y+3z=-27
2x+2y+3z=-3
-3x+2y+2z=-3

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
You didn't specify a solution method.
Hopefully a matrix solution is OK.
[A][x]=[b]
where
[A]=%28matrix%283%2C3%2C%0D%0A3%2C-3%2C+3%2C+%0D%0A2%2C2%2C3%2C%0D%0A-3%2C2%2C2%29%29%0D%0A
[x]=%28matrix%283%2C1%2C%0D%0Ax%2Cy%2Cz%29%29%0D%0A
[b]=%28matrix%283%2C1%2C%0D%0A-27%2C-3%2C-3%29%29%0D%0A
We then need to find the inverse of [A]([Ainv]) and matrix multiply by [b] to get [x].
[A][x]=[b]
[x]=[Ainv][b]
[Ainv]=(1/63)*
[Ainv][b]=(1/63)*
[x]=%28matrix%283%2C1%2C%0D%0A1%2C5%2C-5%29%29%0D%0A
x=1
y=5
z=-5