Question 1191083: he body temperatures in degrees Fahrenheit of a sample of adults in one small town are:
97.9 99.8 98.2 97.3 97.4 98.1 97.7 96.9 99.7 99.9 99.6
Assume body temperatures of adults are normally distributed. Based on this data, find the 99% confidence interval of the mean body temperature of adults in the town. Enter your answer as an open-interval (i.e., parentheses) accurate to 3 decimal places. Assume the data is from a normally distributed population.
99% C.I.
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! mean is 98.409
s=1.126
99% CI half-interval is t (0.995,df=10)*s/sqrt(n)=3.169*1.126/sqrt(11)=1.076
interval is mean+/- half-interval or (97.333 deg, 99.485 deg)
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