SOLUTION: An organization had 14 employees. There are 9 female employees and 5 male employees. How many different teams of 5 people can be chosen from these employees where there are 3 wo

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Question 1191053: An organization had 14 employees. There are 9 female employees and 5 male employees.
How many different teams of 5 people can be chosen from these employees where there are 3 women and 2 men?

Answer by ikleyn(52787) About Me  (Show Source):
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An organization had 14 employees. There are 9 female employees and 5 male employees.
How many different teams of 5 people can be chosen from these employees where there are 3 women and 2 men?
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You can choose 3 women from 9 female employees by  C%5B9%5D%5E3 = %289%2A8%2A7%29%2F%281%2A2%2A3%29 = 84 ways.


You can choose 2 men from 5 male employees by  C%5B5%5D%5E2 = %285%2A4%29%2F%281%2A2%29 = 10 ways.


Next, you can combine these partial teams by 84*10 = 840 ways, obtaining different team every time.



ANSWER.  There are 840 different teams.


Solved.

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This problem combines conceptions of COMBINATIONS and Fundamental Counting principle.

For this conceptions and a variety similar solved and different problems, see the lessons
    - Introduction to Combinations
    - PROOF of the formula on the number of Combinations
    - Problems on Combinations
    - Fundamental counting principle problems
    - OVERVIEW of lessons on Permutations and Combinations
in this site.

Also,  you have this free of charge online textbook in ALGEBRA-II in this site
    - ALGEBRA-II - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic  "Combinatorics: Combinations and permutations".


Save the link to this textbook together with its description

Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson

into your archive and use when it is needed.