|
Question 1191010: Find the equation of the line passing through the point (6,3) that is perpendicular to the line 4x−5y=−10
Found 4 solutions by Alan3354, MathLover1, ikleyn, greenestamps: Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! Find the equation of the line passing through the point (6,3) that is perpendicular to the line 4x−5y=−10
-----------------
Step 1, find the slope of the given line, call it m1.
---
The slope of lines perpendicular is the negative inverse of m1, which is -1/m1. Call that m.
-----
Step 2, use y-y1 = m*(x-x1) where (x1,y1) is the point (6,3)
Answer by MathLover1(20855) (Show Source): Answer by ikleyn(53937) (Show Source): Answer by greenestamps(13367) (Show Source):
You can put this solution on YOUR website!
The equation of any line perpendicular to the line 4x-5y=-10 will have the form 5x+4y=C for some constant C. Note that to get that form, the two coefficients are switched, and the sign is changed.
To get the equation you want, simply substitute the given values x=6 and y=3 to find the value of C.
5x+4y = 5(6)+4(3) = 30+12 = 42
ANSWER: 5x+4y=42
|
|
|
| |