SOLUTION: translate the given verbal expression into algebraic expression. 1. In two consecutive integers, the sum of three fifths the first and one fourth the second is 13.

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: translate the given verbal expression into algebraic expression. 1. In two consecutive integers, the sum of three fifths the first and one fourth the second is 13.      Log On


   

Question 1190704: translate the given verbal expression into algebraic expression.
1. In two consecutive integers, the sum of three fifths the first and one fourth the second is 13.
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Just literally follow what the description says, exactly.

%283%2F5%29n%2B%281%2F4%29%28n%2B1%29=13----------EXACTLY the given sentence, with the two integers being n and n+1.

Answer by ikleyn(52782) About Me  (Show Source):
You can put this solution on YOUR website!
.

The literal translation is

    %283%2F5%29n + %281%2F4%29%28n%2B1%29 = 13.



When translate in this way, you must check if it makes sense:

you should check that such integer number n does really exist.



For it, solve equation

    %283%2F5%29n + %281%2F4%29%28n%2B1%29 = 13.


Multiply both sides by 4*5 = 20

    12n + 5(n+1) = 13*20

    12n + 5n = 260 - 5

       17n   =    255

         n   =     255/17 = 15.


You get this integer number n= 15, and it confirms that the translation does make sense.

Solved.