SOLUTION: Find the lengths of the missing sides if side a is opposite angle A, side b is opposite angle B, and side c is the hypotenuse. sin(B) = 1/sqrt( 6), a = 4

Algebra ->  Trigonometry-basics -> SOLUTION: Find the lengths of the missing sides if side a is opposite angle A, side b is opposite angle B, and side c is the hypotenuse. sin(B) = 1/sqrt( 6), a = 4      Log On


   



Question 1190680: Find the lengths of the missing sides if side a is opposite angle A, side b is opposite angle B, and side c is the hypotenuse.
sin(B) = 1/sqrt( 6), a = 4

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Find the lengths of the missing sides if side a is opposite angle A, side b is opposite angle B, and side c is the hypotenuse.
sin(B) = 1/sqrt(6), a = 4
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It's a right triangle.
B = ~ 22.095 degs
A = 90 - B = 65.9
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sin(A) = 0.9129
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a/sin(A) = b/sin(B)
b = a*sin(B)/sin(A)
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c = sqrt(a^2 + b^2)