Question 1190670: The altitudes (in kilometers) of atmosphere at which helium
is found in majority in 10 different cities are listed.
938.5 927.0 929.5 930.3 934.3 936.0 926.2 930.5 924.8 870.71
Can you help me with this homework question by explaining it step-by-step please? Thanks!
Found 2 solutions by Stelless, ikleyn:
Answer by Stelless(3)   (Show Source):
You can put this solution on YOUR website! The range of the data set is:
This is an indication of how wide 'spread' your data is. The higher the range. The farther apart your highest and lowest value (giving us information about the deviation of all the values from each other).
For this problem you will most likely want to put your data set into order:
"870.71, 924.8, 926.2, 927.0, 929.5, 930.3, 930.5, 934.3, 936.0, 938.5"
For (a) We take the Highest Value (938.5) and subtract this from the lowest value (870.71):
a) 67.79
For (b) We've been asked to change our data set, this now looks like:
"807.71, 924.8, 926.2, 927.0, 929.5, 930.3, 930.5, 934.3, 936.0, 938.5"
We still calculate the range the same way (Highest - Lowest), but we now have a new lowest term:
b) 130.79
By switching our lowest term we've almost doubled our range. This means that we can expect many more values (altitudes) from our experiment as it has a higher range.
I hope that helped! Good luck :^)
Answer by ikleyn(52890)  (Show Source):
You can put this solution on YOUR website! .
The altitudes (in kilometers) of atmosphere at which helium
is found in majority in 10 different cities are listed.
938.5 927.0 929.5 930.3 934.3 936.0 926.2 930.5 924.8 870.71
Can you help me with this homework question by explaining it step-by-step please? Thanks!
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NEITHER your post NOR the answer from the other tutor make sense.
Your post does not makes sense, because it even does not contain a question.
The other tutor's response does not make sense, since it tries to answer a non-existing question.
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It is why I prefer to kill (to delete) such posts with no questions as soon as they come to the forum,
not allowing any useless and counter-productive discussions.
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