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Events A & B are independent. Suppose Event A occurs with a probability 0.60 and
Event B occurs with a probability of 0.74.
A) Compute the probability that B occurs but A does not occur.
B) Compute the probability that either A occurs without B or A and B both occur.
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Since events A and B are independent, the probability
P(A & B) = P(A)*(P(B) = 0.60*0.74 = 0.444.
(A) the probability that B occurs but A does not occur = P(B) - P(A & B) = 0.74 - 0.444 = 0.296. ANSWER
(B) the probability that either A occurs without B or (A & B) both occur =
= (P(A) - P(A & B)) + P(A & B) = P(A) = 0.60. ANSWER
Solved.
