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| Question 1190592:  on monday, revlien paid 66 pesos for 3 doughnuts and 2 cups of coffee. on tuesday, she paid 69 pesos for 2 doughnuts and 3 cups of coffee. how much did he pay for 1 doughnut and 1 cup of coffee on a wednesday?
 
 Found 2 solutions by  ikleyn, math_tutor2020:
 Answer by ikleyn(52879)
      (Show Source): 
You can put this solution on YOUR website! . on monday, revlien paid 66 pesos for 3 doughnuts and 2 cups of coffee.
 on tuesday, she paid 69 pesos for 2 doughnuts and 3 cups of coffee.
 how much did he pay for 1 doughnut and 1 cup of coffee on a wednesday?
 ~~~~~~~~~~~~~~~
 
 
 This problem is intended for mental solution.
 
 
 
 
Add her purchases on Monday and Tuesday:
    she bought 3+2 = 5 doughnuts and 2+3 = 5 cups of coffee, in total,
    spending 66 + 69 = 135 pesos.
HENCE, one doughnut and one cup of coffee cost  1/5  of it, i.e.  135/5 = 27 pesos.   
ANSWER.  On Wednesday, she must pay 27 pesos.
---------------
 
 Solved.
 
 Notice that I did not solve any systems of equations.
 
 I even did not write them.
 
 
 It is a classic type of problems, that seem to be solved
 using equations,  but actually  MUST  be solved mentally.
 
 Solving mentally is a  GOOD  STYLE  solving such problems.
 
 
 It is what the teachers expect to get from their students,
 when they give them such problems.
 
 
 It is what the interviewers expect to get from the candidates
 when they interview them somewhere in  Microsoft or  Google.
 
 
 But the final goal of teachers,  when they give such problems,  is to develop
 the student's mind  FLEXIBLE  and  CREATIVE,  instead of making it dogmatic.
 
 
 
Answer by math_tutor2020(3817)
      (Show Source): 
You can put this solution on YOUR website! d = cost of 1 doughnut
 c = cost of 1 coffee
 costs are in pesos
 
 Setting up the cost for Monday
 3d = cost of 3 doughnuts
 2c = cost of 2 coffees
 3d+2c = total cost of the 5 items overall
 3d+2c = 66 pesos
 
 Let's solve for c
 3d+2c = 66
 2c = 66-3d
 c = (66-3d)/2
 c = (66/2)-(3d/2)
 c = 33 - 1.5d
 I'll use this later on.
 
 Setting up the cost for Tuesday
 2d = cost of 2 doughnuts
 3c = cost of 3 coffees
 2d+3c = total cost of these 5 new items
 2d+3c = 69 pesos
 
 Apply substitution
 2d+3c = 69
 2d+3( c ) = 69
 2d+3( 33-1.5d ) = 69 ... c replaced with 33-1.5d
 2d+99-4.5d = 69
 -2.5d = 69-99
 -2.5d = -30
 d = -30/(-2.5)
 d = 12
 It costs 12 pesos for 1 doughnut
 
 c = 33 - 1.5d
 c = 33 - 1.5(12)
 c = 33 - 18
 c = 15
 It costs 15 pesos for 1 coffee
 
 Check for Monday:
 3d+2c = 66
 3*12+2*15 = 66
 36+30 = 66
 66 = 66 that works out
 
 Check for Tuesday:
 2d+3c = 69
 2*12+3*15 = 69
 24+45 = 69
 69 = 69 that works out as well
 
 We've confirmed we have the correct unit prices for each food item.
 
 For Wednesday, she bought 1 doughnut and 1 coffee
 So the amount paid is d+c = 12+15 = 27 pesos
 This excludes any kind of tax or extra surcharges.
 
 Answer: 27 pesos
 
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