SOLUTION: At a certain zoo, p pounds of food will feed a group of w walruses for t weeks. How many pounds of food will only two of the walruses eat in three days? a) (2pt)/(7w) b) (3w)/(7p

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Question 1190462: At a certain zoo, p pounds of food will feed a group of w walruses for t weeks. How many pounds of food will only two of the walruses eat in three days?
a) (2pt)/(7w)
b) (3w)/(7pt)
c) (7pt)/(2w)
d) (6p)/(7tw)
e) (42tw)/p
Found 2 solutions by ikleyn, math_tutor2020:
Answer by ikleyn(52805) About Me  (Show Source):
You can put this solution on YOUR website!
At a certain zoo, p pounds of food will feed a group of w walruses for t weeks.
How many pounds of food will only two of the walruses eat in three days?
a) (2pt)/(7w)
b) (3w)/(7pt)
c) (7pt)/(2w)
d) (6p)/(7tw)
e) (42tw)/p
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From the context, each creature eats  p%2F%287tw%29  pounds of food per day.


Hence, two creatures will eat  %283%2A2%2Ap%29%2F%287tw%29 = %286p%29%2F%287tw%29  pounds of food in three days.    ANSWER

Solved, answered and explained.



Answer by math_tutor2020(3817) About Me  (Show Source):
You can put this solution on YOUR website!

w = number of walruses
t = number of weeks
p = amount of food (in pounds) to feed w walruses for t weeks

t weeks = 7t days
w walruses need p pounds of food
1 walrus needs p/w pounds of food
This is for a timespan of t weeks, aka 7t days

p/w pounds of food for 1 walrus over 7t days
p/(7tw) pounds of food for 1 walrus for 1 day.
2p/(7tw) pounds of food for 2 walruses for 1 day.

Triple that amount to arrive at the final answer.

Answer: (6p)/(7tw)