SOLUTION: The width of a rectangle is 25.7 feet less than four times its length, and the perimeter is 29.6 feet. Find the length and the width of the rectangle

Algebra ->  Rectangles -> SOLUTION: The width of a rectangle is 25.7 feet less than four times its length, and the perimeter is 29.6 feet. Find the length and the width of the rectangle      Log On


   

Question 1190435: The width of a rectangle is 25.7 feet less than four times its length, and the perimeter is 29.6 feet. Find the length and the width of the rectangle
Found 3 solutions by josgarithmetic, MathTherapy, ikleyn:
Answer by josgarithmetic(39630) About Me  (Show Source):
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L, the length

L%2B%284L-25.7%29=29.6
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Answer by MathTherapy(10556) About Me  (Show Source):
You can put this solution on YOUR website!

The width of a rectangle is 25.7 feet less than four times its length, and the perimeter is 29.6 feet. Find the length and the width of the rectangle
L%2B%284L-25.7%29=29.6

B E W A R E !! JOSGARITHMETIC's equation, above, will NOT give you the correct value for the rectangle's length.

Hence, width will also be INCORRECT!

Answer by ikleyn(52878) About Me  (Show Source):
You can put this solution on YOUR website!
.
The width of a rectangle is 25.7 feet less than four times its length,
and the perimeter is 29.6 feet. Find the length and the width of the rectangle
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            It is to replace wrong solution from @josgarithmetic . . . 


Let L be the length, in feet; then the width is  4L-25.7 feet.


Write equation for the half of the perimeter as you read the problem


   L + (4L - 25.7) = 14.8   feet   ( where 14.8 = 29.6/2 )


Simplify and find L


    5L            = 14.8 + 25.7

    5L            =     40.5

     L            =     40.5 / 5 = 8.1.


Thus the length is  8.1 feet;  the width is  4*8.1-25.7 = 6.7 feet.    ANSWER


CHECK.  The perimeter is  2*(8.1+6.7) = 2*14.8 = 29.6  ft.    ! Precisely Correct !

Solved.