SOLUTION: the perimeter of a rectangle is 8x+2 and the width is x+2. Express the area as a trinomial.

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Question 119036: the perimeter of a rectangle is 8x+2 and the width is x+2. Express the area as a trinomial.
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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the perimeter of a rectangle is 8x+2 and the width is x+2. Express the area as a trinomial.
:
Given the Perimeter:
2L + 2W = 8x+2
:
Given the width as (x+2)
2L + 2(x+2) = 8x+2
Find L
2L + 2x + 4 = 8x+2
2L = 8x - 2x + 2 - 4
2L = 6x - 2
L = 3x - 1; divided equation by 2
:
Area = L * W
Area = (3x-1)*(x+2)
FOIL
Area = 3x^2 + 6x - x - 2
Area = 3x^2 + 5x - 2, is the trinomial representing the area
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