SOLUTION: A triangle with sides of length 36 cm, 77 cm, and 85 cm are inscribed in a circle. Inside the triangle a second circle is inscribed. What is the area in square centimetres, between

Algebra ->  Triangles -> SOLUTION: A triangle with sides of length 36 cm, 77 cm, and 85 cm are inscribed in a circle. Inside the triangle a second circle is inscribed. What is the area in square centimetres, between      Log On


   



Question 1190327: A triangle with sides of length 36 cm, 77 cm, and 85 cm are inscribed in a circle. Inside the triangle a second circle is inscribed. What is the area in square centimetres, between the two circles?
Answer by ikleyn(52765) About Me  (Show Source):
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A triangle with sides of length 36 cm, 77 cm, and 85 cm are inscribed in a circle.
Inside the triangle a second circle is inscribed. What is the area in square centimetres,
between the two circles?
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Notice that the given triangle is a right-angled triangle, since

    36^2 + 77^2 = 7225 = 85^2.


Since this triangle is inscribed to the larger circle, its hypotenuse is the DIAMETER of the larger circle.


Thus the larger circle's diameter is 85 cm;  hence, the larger circle's radius is R = 85/2 = 42.5 cm.


Next, the radius of the inscribed circle is (as for any right angled triangle)

    r = %28a%2Bb-c%29%2F2 = %2836%2B77-85%29%2F2 = 14 cm

where "a" and "b" are the legs, 36 cm and 77 cm, while "c" is the hypotenuse 85 cm.


Now the area between the circles is  

    pi%2AR%5E2+-+pi%2Ar%5E2 = pi%2A%2842.5%5E2-14%5E2%29 = 1610.25%2Api = 1610.25%2A3.14159 = 5058.745 cm^2.    ANSWER

Solved.