SOLUTION: Find the area, in square units, of an isosceles triangle whose sides have lengths 29, 29, and 42 cm without using Heron's formula

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Question 1190312: Find the area, in square units, of an isosceles triangle whose sides have lengths 29, 29, and 42 cm without using Heron's formula
Answer by ikleyn(52756) About Me  (Show Source):
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Find the area, in square units, of an isosceles triangle whose sides have lengths
29, 29, and 42 cm without using Heron's formula.
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In isosceles triangle, the altitude drawn to the base, is the median at the same time.


It means that the altitude divides the triangle in two congruent right anfled triangle.


So, we can find the altitude length h in this way by applying thr Pythagorean formula 


    h = sqrt%2829%5E2+-+%2842%2F2%29%5E2%29 = sqrt%2829%5E2-21%5E2%29 = sqrt%28400%29 = 20.


Then the area of the given triangle is half the product of the base by the altitude


    the area = %281%2F2%29%2A42%2A20 = 42*10 = 420 square centimeters.    ANSWER

Solved.