SOLUTION: I have to graph this equation: f(x)=x^2(x+2)(x-1) I know that x-intercepts are -2,+1 I am not sure what the x^2 tells about the graph?

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Question 1190271: I have to graph this equation: f(x)=x^2(x+2)(x-1)
I know that x-intercepts are -2,+1
I am not sure what the x^2 tells about the graph?

Found 2 solutions by Solver92311, ikleyn:
Answer by Solver92311(821) About Me  (Show Source):
You can put this solution on YOUR website!


The graph is also tangent to the -axis at the origin.

.

John

My calculator said it, I believe it, that settles it

From
I > Ø

Answer by ikleyn(52803) About Me  (Show Source):
You can put this solution on YOUR website!
.

The factor x^2 of the polynomial tells you that the plot of the polynomial TOUCHES x-axis at x= 0,
without going from negative values to positive and vice versa, at x= 0.


In particular, first derivative of this function is zero at x= 0, which means that the tangent line to the plot
is horizontal at x= 0.


By the way, in the Internet, there are sites what provide you free of charge plotting tools, so you can produce
any plot of any function as easy as the tutors do it, ON YOUR OWN.


It is only the matter of pressing buttons and printing formulas . . .


One of such sites is www.desmos.com


Alternatively, you may use your graphing calculator to make a plot.


Making plots for students is not a tutors' job.