SOLUTION: Timothy has a total of seventy-one coins. If he had 3 times the number of quarters and one-half the number of pennies, he would have $15.22 more. How much money does he have?

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Question 1190240: Timothy has a total of seventy-one coins. If he had 3 times the number of quarters and one-half the number of pennies, he would have $15.22 more. How much money does he have?
Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


The setup is easy....

Let x = # of quarters
Then 71-x = # of pennies

Total value of the coins in cents: 25(x)+1(71-x) = 24x+71

Number of quarters if he had 3 times as many: 3x
Number of pennies if he had half as many: (1/2)(71-x)

Total value of the new numbers of coins: 25(3x)+1((1/2)(71-x))

The new total value is 1522 cents more than the original:

25%283x%29%2B1%28%281%2F2%29%2871-x%29%29=24x%2B71%2B1522

Unfortunately, solving that equation gives a non-integer value for x, which is impossible.

The problem is faulty as given. Correct the statement of the problem and re-post.

Or take the correct numbers in the problem and set up and solve the problem yourself using the method shown.