SOLUTION: A boat on a river travels downstream between two points, 80 mi apart, in 1 h. The return trip against the current takes 2.5 hours What is the boat's speed (in still water)?

Algebra ->  Equations -> SOLUTION: A boat on a river travels downstream between two points, 80 mi apart, in 1 h. The return trip against the current takes 2.5 hours What is the boat's speed (in still water)?      Log On


   



Question 1190128: A boat on a river travels downstream between two points, 80 mi apart, in 1 h. The return trip against the current takes 2.5 hours
What is the boat's speed (in still water)?

Found 2 solutions by Alan3354, ikleyn:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
A boat on a river travels downstream between two points, 80 mi apart, in 1 h. The return trip against the current takes 2.5 hours.
What is the boat's speed (in still water)?
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Find the 2 speeds, downstream and upstream.
The boat's speed is the average of the 2.

Answer by ikleyn(52776) About Me  (Show Source):
You can put this solution on YOUR website!
.
A boat on a river travels downstream between two points, 80 mi apart, in 1 h.
The return trip against the current takes 2.5 hours.
What is the boat's speed (in still water)?
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Let  u  be the boat speed in still water (in miles per hour, mph).

Let  v  be the rate of the current, in mph.


Then  the boat's  effective speed downstream is  u+v  mph,
while the boat's  effective speed upstream   is  u-v  mph.


Now, "speed" equation for boat floating upstream is 

80%2F2.5 = u - v    (1)    (speed upstream = the distance divided by time upstream)


Next, "speed" equation for boat floating downstream is 

80%2F1 = u + v    (2)    (speed downstream = the distance divided by time  downstream)



Simplify equations (1) and (2)


u - v = 32     (3)
u + v = 80     (4)


Now add equations (3) and (4) to eliminate "v". You will get


2u = 80 + 32 = 112  ====>  v = 112%2F2 = 56.


ANSWER.  The rate of the boat in still water is 56 miles per hour.    ANSWER

Solved.