SOLUTION: solve using synthetic division (4x²+5x+1)÷(x+1)

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Question 119010: solve using synthetic division
(4x²+5x+1)÷(x+1)

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

Let's simplify this expression using synthetic division


Start with the given expression %284x%5E2+%2B+5x+%2B+1%29%2F%28x%2B1%29

First lets find our test zero:

x%2B1=0 Set the denominator x%2B1 equal to zero

x=-1 Solve for x.

so our test zero is -1


Now set up the synthetic division table by placing the test zero in the upper left corner and placing the coefficients of the numerator to the right of the test zero.
-1|451
|

Start by bringing down the leading coefficient (it is the coefficient with the highest exponent which is 4)
-1|451
|
4

Multiply -1 by 4 and place the product (which is -4) right underneath the second coefficient (which is 5)
-1|451
|-4
4

Add -4 and 5 to get 1. Place the sum right underneath -4.
-1|451
|-4
41

Multiply -1 by 1 and place the product (which is -1) right underneath the third coefficient (which is 1)
-1|451
|-4-1
41

Add -1 and 1 to get 0. Place the sum right underneath -1.
-1|451
|-4-1
410

Since the last column adds to zero, we have a remainder of zero. This means x%2B1 is a factor of 4x%5E2+%2B+5x+%2B+1

Now lets look at the bottom row of coefficients:

The first 2 coefficients (4,1) form the quotient

4x+%2B+1


So %284x%5E2+%2B+5x+%2B+1%29%2F%28x%2B1%29=4x+%2B+1

You can use this online polynomial division calculator to check your work