SOLUTION: MARTIN AND TOM SHARE SUM OF MONEY IN THE RATIO 4:3 . MARTIN SHARE WAS $19.80 . WHAT WAS THE EXACT SUM OF MONEY THEY HAD TO SHARE?

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: MARTIN AND TOM SHARE SUM OF MONEY IN THE RATIO 4:3 . MARTIN SHARE WAS $19.80 . WHAT WAS THE EXACT SUM OF MONEY THEY HAD TO SHARE?      Log On


   



Question 1190065: MARTIN AND TOM SHARE SUM OF MONEY IN THE RATIO 4:3 . MARTIN SHARE WAS $19.80 . WHAT WAS THE EXACT SUM OF MONEY THEY HAD TO SHARE?
Answer by math_tutor2020(3817) About Me  (Show Source):
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The ratio 4:3 describes the portions of money Martin and Tom get in that order.
If $7 was the total sum being shared, then Martin would get $4 while Tom gets $3, since 7 = 4+3.

The ratio 4:3 can be scaled up to 4x:3x for some positive real number x.
Martin gets 4x dollars
Tom gets 3x dollars
The total sum of money split up is 4x+3x = 7x.

Since Martin receives 4x dollars, and we're told he got $19.80, we can use these two facts to form the steps below
4x = 19.80
x = 19.80/4
x = 4.95

This x value leads to
total = 7x
total = 7*4.95
total = 34.65

Side note: To compute Tom's share, plug that x value into 3x. You should get 3x = 3*4.95 = 14.85. Or you could compute 34.65 - 19.80 = 14.85


Final Answer: $34.65