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| Question 1190043:  U={a,b,c,d,e,f,g,h,i} A={a,c,g,h} B={a,b,c,d} C={b,c,g,i}
 (A U B') n (C n B')
 Answer by math_tutor2020(3817)
      (Show Source): 
You can put this solution on YOUR website! Universal set = U = {a,b,c,d,e,f,g,h,i}
 A = {a,c,g,h}
 B = {a,b,c,d}
 C = {b,c,g,i}
 
 B' = set of everything NOT in set B
 B' = {
 a,b,c,d,e,f,g,h,i}B' = {e,f,g,h,i}
 I started with the universal set, then crossed off stuff I found in set B
 An item is either in set B, or it is in set B', but not both sets at once.
 
 Let's union sets A and B'
 A = {a,c,g,h}
 B' = {e,f,g,h,i}
 A u B' = {a,c,g,h    e,f,g,h,i}
 A u B' = {a,c,e,f,g,h,i}
 As the third step shows, I simply glued the two sets together to form a larger one. The color coding shows where the items are coming from. Then I sorted the items and tossed any duplicates.
 
 Next, we'll intersect sets C and B'
 C = {b,c,g,i}
 B' = {e,f,g,h,i}
 C n B' = {g,i}
 This is the set of items found in BOTH C and B'
 
 The last step is to intersect the two results from each previous section
 D = A u B' = {a,c,e,f,g,h,i}
 E = C n B' = {g,i}
 D n E = (A u B') n (C n B')
 D n E = {g,i} is the final answer
 
 Side note: be sure to not mix up the notation for the union symbol and the universal set. I decided to go with lowercase 'u' to represent the union symbol, and uppercase U to represent the universal set. The n refers to the intersection symbol.
 
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